Friction is very crucial in our daily lives, as they help to prevent car tires from slipping on the ice in winter, and they make it possible for a car to stop when braking. A person jumping with a parachute descends feels an air drag, which is the force of fluid friction exerted by the air on a moving body. Furthermore, a ball that rolls on the ground will slow down until it eventually stops due to rolling friction, both of these are examples of contact forces.
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Jetzt kostenlos anmeldenFriction is very crucial in our daily lives, as they help to prevent car tires from slipping on the ice in winter, and they make it possible for a car to stop when braking. A person jumping with a parachute descends feels an air drag, which is the force of fluid friction exerted by the air on a moving body. Furthermore, a ball that rolls on the ground will slow down until it eventually stops due to rolling friction, both of these are examples of contact forces.
If two bodies touch each other directly, they are in contact. Contact forces are used to explain the interaction between two bodies. Some examples of contact forces include the normal force and the frictional force. There are two broad types of friction forces that all the others fall into; static and kinetic friction. In this article, we will focus on the force of static friction and explain its mathematical representation. We will also discuss the differences between static and kinetic friction.
If we have a box on the floor and we try to push it with some force, the box may just stand still and not move. This is due to the static friction force. The static frictional force occurs when the object and surface are at rest relative to each other. There is no motion of one relative to the other. Due to static friction, an object will stay still on a surface without slipping. The floor exerts a static friction force that is equal in magnitude and opposite in direction to the applied force until the force applied is greater than the maximum static frictional force. The static friction force can be shown as \(\overset\rightharpoonup{f_{\mathrm s}}\).
It is important to note that this has nothing to do with Newton's Third Law, as the action-reaction force pair always acts on different objects.
In the figure above, we see a box that is initially at rest. The normal force \(\overset\rightharpoonup N\) is upwards and is exerted on the box by the floor, while the weight \(\overset\rightharpoonup W\) acts downward. Because the box is at equilibrium, the magnitudes of the normal force and weight are equal.
Then a force \(\overset\rightharpoonup F\) is applied on the box pulling it to the right, over time the magnitude of this applied force is gradually increased. The box will stay at rest for some time. This is because even if the force is increasing, the force of static friction is increasing as well to balance the magnitude with force \(\overset\rightharpoonup F\).
The force needed to move the box is equal and opposite to the maximum static friction force. The maximum value for the static friction force is shown as \({(f_{\mathrm s})}_\max\) and it is proportional to the magnitude of the normal force. The proportionality factor is shown as \(\mu_{\mathrm s}\) and is called the coefficient of static friction. Once the maximum static friction force is overcome, the box will begin to slide to the right.
The real value of static friction might range from zero (when there is no force exerted on the object) to a maximum value, which is mathematically represented as
$$f_s\leq{(f_s)}_{max}=\mu_sN.$$
According to the mathematical representation, the static friction relationship is between magnitudes, as the static friction magnitude is proportional to both the magnitude of the normal force and the roughness between the two surfaces in contact. Therefore, directions do not matter like in vectorial relationships.
So, what does this formula mean?
We mentioned that there is a limit where the force \(\overrightarrow F\) is greater than the maximum value of the static friction force. If the limit is surpassed, the box begins to move. When the static friction force is at a maximum and the motion is about to start, the frictional force is called the limiting friction. When motion starts, the object will no longer experience static friction. Instead, the object experiences the force of kinetic friction.
If we look at the above graph we see that with an increasing applied force \(\overset\rightharpoonup F\), the magnitude of the static friction force begins to increase as well until it reaches a peak where the magnitude is that of the limiting friction. Afterwards, the object begins to move, and the static friction force is no longer effective, but the kinetic friction force is.
Now let's investigate some examples involving the static friction force.
Questions
a) A box with a mass of \(4\,\mathrm{kg}\) is at rest on a surface. When a force of \(10\,\mathrm N\) is applied to the box it is still at rest, what is the magnitude of static friction force?
b) If the value of maximum static friction force is \(20\,\mathrm N\), what is the coefficient of static friction \(\mu_{\mathrm s}\) for a \(10\,\mathrm kg\) box? (\(g=10\,\frac{\mathrm m}{\mathrm s^2}\))
Solutions
a) When an object is at rest and a force is applied to it, the magnitude of the force is equal to the magnitude of static friction force. Since a force of \(10\,\mathrm N\) is applied, the magnitude of the static friction force is equal to \(10\,\mathrm N\) as well.
b) The magnitude of the maximum static friction force is equal to \(\mu_{\mathrm s}N\).
Since the value of maximum static friction force is \(20\,\mathrm N\), it can be inserted in the place of \({\left(f_s\right)}_\max\). Also, the mass of the object is given. So, we can calculate the weight.
$$\begin{align*}\mathrm W&=\mathrm{mg},\\\mathrm W&=\left(4\,\mathrm{kg}\right)\left(10\,\mathrm m/\mathrm s^2\right),\\\mathrm W&=40\,\mathrm N.\end{align*}$$
As the weight and normal force have the same magnitude, we can determine the coefficient of static friction \(\mu_{\mathrm s}\).
$$\begin{align*}f_{\mathrm s}&=\mu_{\mathrm s}N,\\\mu_{\mathrm s}&=\frac{{\mathrm f}_{\mathrm s}}{\mathrm N},\\\mu_{\mathrm s}&=\frac{20\,\mathrm N}{40\,\mathrm N},\\\mu_{\mathrm s}&=0.5.\end{align*}$$
So, what is the difference between static friction and kinetic friction?
The differences between the forces of static friction and kinetic friction can be summarised as:
The static friction force is applied while the object is at rest.
When the exerted force \(\overset\rightharpoonup F\) is at a value at which the motion starts, the formula can be used to calculate the magnitude of static friction force.
If the force \(\overset\rightharpoonup F\) is less than this value, then the magnitude of static friction force should be less than \(\mu_{\mathrm s}N\). In this case, the magnitude of static friction force will simply be equal to the magnitude of the force applied \(\overset\rightharpoonup F\).
The type of friction where there is the maximum value of static friction force and the motion is about to start is called the limiting friction.
The difference between static and kinetic friction force is that the static one is applied while the object is stationary, and the kinetic one is applied while the object is moving. Static means standing, kinetic moving.
In the context of friction, a static force is the force that a surface exerts on an object pressed against it. This force is directly opposed to the normal force and is proportional to the normal force.
The equation for finding static friction is Fs = μs N, where Fs is the static frictional force, μs is the coefficient of static friction, and N is the normal force.
Friction is not a contact force.
False.
A car can brake and stop without the friction force.
False.
The static friction force is applied while the object is stationary.
True.
If the force \(\overrightarrow F\) is exerted on the box pulling it to the right, and its magnitude is increasing with time, the box stays at rest for some time. This is because even if the force is increasing, the force of static friction is increasing as well to cancel the applied force and maintain the box at rest. The force needed to move the box is equal and opposite to the maximum static friction force, \(\mu_{\mathrm s}N\).
True.
The type of friction where there is the ___ value of static friction force and the motion is about to start is called the limiting friction.
Maximum.
The difference between static and kinetic friction force is that the static one is applied while the object is ___, and the kinetic one is applied while the object is ___.
Stationary, moving.
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