## Types of motion graphs

There are **three main types of graphs** used to define the motion of an object in a **straight line**: displacement-time graphs, velocity-time graphs, and acceleration-time graphs.

### Displacement versus time graph

Figure 1 illustrates a displacement-time graph of an object moving at a** constant velocity**. For the displacement-time graph, displacement (denoted by d) is on the y-axis, and time (denoted by t) is on the x-axis.

Figure 1. The displacement-time graph of an object moving at a constant velocity. Usama Adeel – StudySmarter Originals

From such a graph, we can obtain

- the
**distance**covered at any given time, - the
**average velocity**by calculating the slope (gradient) of the graph, and - the
**instantaneous velocity**by calculating the derivative of any point on the curve.

To calculate the slope p of the above graph, we use the following equation:

\[p = \frac{y_2 - y_1}{x_2 - x_1} = \frac{\Delta d}{\Delta t} m/s\]

The **rate of change of displacement is velocity,** so the slope of the displacement-time graph is the velocity.

### Velocity versus time graph

Have a look at the velocity-time graph below:

Figure 2. The velocity-time graph of an object moving at constant velocity. Usama Adeel – StudySmarter Originals

For the velocity-time graph, velocity (v) is on the y-axis, and time (t) is on the x-axis. From this graph, we can find

- the
**velocity**at any given time, - the
**average acceleration**by calculating the slope of the straight line, - the
**instantaneous acceleration**by taking the derivative of any point on the curve, and - the
**displacement of a body**by calculating the area under the curve (between the line and the time axis).

To calculate the slope p of the above graph, we use the following equation:

\[p = \frac{y_2 - y_1}{x_2 - x_1} = \frac{\Delta v}{\Delta t} m/s^2\]

The **rate of change of velocity is acceleration**, so the slope of the velocity-time graph is the acceleration.

Furthermore, the **area under the velocity-time graph gives the distance covered by the object**, which is the displacement.

### Acceleration versus time graph

For an acceleration-time graph, acceleration (a) is given on the y-axis and the time (t) on the x-axis. The acceleration-time graph gives us the acceleration at any given time. Also, the **area under the acceleration-time curve represents a change in velocity****. **

Figure 3. The acceleration-time graph of an object moving at a uniformly increasing acceleration. Usama Adeel – StudySmarter Originals

## Analyzing graphs of motion without numbers

Below we explore how to draw graphs of motion for different scenarios.

### Graphs of Motion: An object at rest

For an object at rest, there will be no change in displacement, which will result in no change in velocity, and because there is no change in the velocity, the change in acceleration will be zero as well.

**Displacement-time graph for an object at rest**

An object at rest will not move. Hence, the **displacement will not change** over the interval of time which is depicted by a flat line parallel to the time axis.

Figure 4. The displacement-time graph of an object at rest. Usama Adeel – StudySmarter Originals

**Velocity-time graph for an object at rest**

The **velocity will be zero** because the object’s displacement doesn’t change. Hence, the graph for an object without its velocity changing over time can be shown with a straight line on the time axis.

Figure 5. The velocity-time graph of an object at rest. Usama Adeel – StudySmarter Originals

**Acceleration-time graph for an object at rest**

The **acceleration will be zero** because the object’s velocity is not changing and the acceleration time graph be a flat line starting from the origin.

Figure 6. The acceleration-time graph of an object at rest. Usama Adeel – StudySmarter Originals

### Graphs of Motion: Objects moving at a constant velocity (distance is increasing over time)

When an object moves at a constant velocity:

- The rate of change of
**displacement**will be**uniformly increasing**. - The
**velocity will be a continuous straight line**with a positive or negative value depending on the direction of movement. **Acceleration will be zero**, so a constant line will pass through the origin.

**Displacement-time graph for an object moving at a constant velocity**

The **slope** of the below graph is **positive**, indicating the movement is in the positive direction (away from the origin). If this curve had been the same but with a negative gradient (towards the origin), it would have depicted displacement in the opposite direction. Also, **displacement is uniformly increasing because the velocity is constant**.

Figure 7. The displacement-time graph of an object moving at a constant speed from rest. Usama Adeel – StudySmarter Originals

Question: Which direction should be considered positive or negative?

Answer: The sign is arbitrary. You can take any direction as either positive or negative.

**Velocity-time graph for an object moving at a constant velocity**

As the slope of the displacement-time graph for a body moving with a constant velocity is **positive** in figure 7, the** velocity is a constant straight line in the positive direction**.

Figure 8. Velocity-time graph of an object moving at a constant speed. Usama Adeel – StudySmarter Originals

**Acceleration-time graph for an object moving at a constant velocity**

As there is **no rate of change of velocity** (constant velocity), the **acceleration will be zero** as well because for acceleration or deceleration to occur, there needs to be a change in velocity as well.

Figure 9. Acceleration-time graph of an object moving at a constant speed. Usama Adeel – StudySmarter Originals

### Graphs of Motion: Objects moving with a constant acceleration (distance is increasing over time)

When an object moves with constant acceleration:

- The displacement-time graph will be a
**curve**with a gradient that becomes**increasingly steeper**. - The rate of change of
**velocity**will be**uniformly increasing.** - Acceleration will be
**constant with a positive value.**

**Displacement-time graph for an object moving with constant acceleration**

Below are the two graphs for displacement vs time. Figure 10 is for constant **acceleration** and figure 11 is for constant **deceleration**.

Figure 10. Displacement-time graph of an object moving at constant acceleration. Usama Adeel – StudySmarter Originals

Figure 11. Displacement-time graph of an object moving at constant deceleration. Usama Adeel – StudySmarter Originals

If you take the tangents at various points on both of the above curves, you will see that the **slope** of the displacement-time graph in figure 10 is becoming **steeper and steeper**. This is an indication that the **velocity is increasing**. In figure 11, the **gradient is gradually decreasing**, which is an indication that the **velocity is decreasing**.

Figure 12. Displacement-time graph of an object moving at constant acceleration. The slope is getting steeper, indicating constant acceleration. Usama Adeel – StudySmarter Originals

Figure 13. Displacement-time graph of an object moving at constant acceleration. The slope is getting flatter, indicating constant deceleration. Usama Adeel – StudySmarter Originals

**Velocity-time graph for an object moving with constant acceleration**

The velocity-time graph for a constant acceleration will be a uniformly increasing line as shown by the figure below.

Figure 14. Velocity-time graph of an object moving at constant acceleration. Usama Adeel – StudySmarter Originals

**Acceleration-time graph for an object moving with constant acceleration**

As the acceleration is not changing over time and is constant, the acceleration-time graph can be represented by a straight line.

Figure 15. Acceleration-time graph of an object moving at constant acceleration. Usame Adeel – StudySmarter Originals

### Graphs of Motion: An object moving at a constant deceleration (distance is increasing over time)

When an object moves with a constant deceleration:

- The displacement-time graph will be a
**curve**with a gradient that becomes more and more horizontal. - The rate of change of
**velocity**will**uniformly decrease**. **Acceleration will be constant**but with a negative value.

**Displacement-time graph for an object moving with constant deceleration**

Because the body is decelerating, the curve is approaching a **constant (unchanged) value**.

Figure 16. Displacement-time graph of an object moving at constant deceleration. StudySmarter Originals – Usama Adeel

**Velocity-time graph for an object moving with constant deceleration**

The velocity-time graph for a constant deceleration will be a uniform line constantly decreasing from some value.

Figure 17. Velocity-time graph of an object moving at constant deceleration. Usama Adeel – StudySmarter Originals

**Acceleration-time graph for an object moving with constant deceleration**

The constant line with a negative acceleration shows that an object is decelerating with a constant value.

Figure 18. Acceleration-time graph of an object moving at constant deceleration. Usama Adeel – StudySmarter Originals

### Graphs of Motion: Throwing an object straight up with the object returning to the thrower

For this scenario, an object, let’s say a ball, is thrown upwards in such a way that it lands in the thrower’s hand after some time. Air resistance is negligible, and the only forces acting on the ball come from the thrower (to throw the ball upwards) and the gravitational pull on the ball until it lands in the thrower’s hand. The upwards direction is considered as positive.

**Displacement-time graph for an object thrown straight up**

The displacement-time graph for an object thrown straight up and then landing in the thrower's hand is shown below.

Figure 19. Displacement-time graph of an object thrown in the air and caught at the same height. Usama Adeel – StudySmarter Originals

Once the ball is thrown in the air, the ball’s displacement increases because we have taken the upwards direction as positive. As it reaches the top, the gradient of the displacement-time graph will be zero for a brief moment, indicating that the ball is changing its direction and will move downwards from here on. Therefore, the graph will move downwards until the ball reaches its original position.

But why is the graph a curve and not a straight line? The **acceleration due to gravity is constant,** with a value of 9.81m/s^{2}. So, from the moment the ball is thrown until it is caught, the deceleration due to gravity and the acceleration due to free-fall will be constant and different from zero.

**Velocity-time graph for an object thrown straight up**

The velocity-time graph for an object thrown straight up and then landing in the thrower's hand is shown below.

Figure 20. Velocity-time graph of an object thrown in the air and caught at the same height. Usama Adeel – StudySmarter Originals

The ball is thrown upwards with some initial velocity u. As the ball reaches the top, its velocity decreases uniformly until it reaches zero, where the ball is at rest for a brief moment. Afterwards, the ball moves downwards with a uniformly increasing velocity.

As the distance travelled will be the same upwards and downwards because of negligible air resistance, the initial velocity will be equal to the final velocity -u. So, the **area of both regions A and B will be the same** in this case.

Why is the slope of the graph negative and not positive after u reaches zero? As the upwards direction is taken as positive, once the direction of the ball changes at the top, the motion will be downwards in the negative direction with a constant acceleration of free fall.

**Acceleration-time graph for an object thrown straight up**

The acceleration-time graph for an object thrown straight up and then landing in the thrower's hand is shown below.

Figure 21. Acceleration-time graph of an object thrown in the air and caught at the same height. Usama Adeel – StudySmarter Originals

The **acceleration is a constant -9.81m/s ^{2} throughout the displacement** as the velocity-time graph is uniformly decreasing.

After the ball is tossed in the air, the gravitational force works in the direction opposite to the upwards motion. Since the upwards motion is taken to be positive, the gravitational force will be negative. Once the ball reaches its peak, the ball changes direction. Hence, the gravitational force will continue to be negative.

## Graphs of Motion - Key takeaways

There are three main types of graphs concerning linear motion: the displacement-time graph, the velocity-time graph, and the acceleration-time graph

- From the displacement-time graph, you can calculate the average velocity and instantaneous velocity by calculating the slope of the graph.
- From the velocity-time graph, you can calculate the average acceleration by finding the slope of the graph and instantaneous acceleration by finding the slope at a particular point.
- The area under the velocity-time graph represents displacement.
- The area under the acceleration-time graph represents a change in velocity.

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##### Frequently Asked Questions about Graphs of Motion

How to interpret graphs of motion?

You can interpet graphs of motion as follows: The gradient of the graph and area under the graph give information about the displacement, velocity, and acceleration depending on what type of linear motion graph we are considering. For example, the slope of a displacement-time graph gives the average velocity.

What are the graphs of motion?

The graphs of motion are the displacement-time graph, the velocity-time graph, and the acceleration-time graph.

What type of graph is used to display motion?

Graphs of motion are used to display linear motion. The graphs of motion are the displacement-time graph, the velocity-time graph, and the acceleration-time graph.

How to work out velocity of motion graphs?

You can work out the velocity of motion graphs as follows:

- You can find the average velocity by calculating the slope of the displacement-time graph.
- You can find the velocity at any given time on a velocity-time graph.
- You can find the velocity by calculating the area under the acceleration-time curve from an acceleration-time graph.

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