Did you know that there can be two exact waves, where the only difference is that one of them has been shifted from a certain point of reference? A wave is a spatial and temporal process in which energy is transported. A periodic wave is a wave that repeats as a function of position and time. Mathematically, periodic waves are used to describe oscillations and simple harmonic motion, which describes the movement of spring-mass systems. This type of wave is described by two characteristics: a magnitude and a phase. In this article, we will discuss the concept of the phase angle in a periodic wave.
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Jetzt kostenlos anmeldenDid you know that there can be two exact waves, where the only difference is that one of them has been shifted from a certain point of reference? A wave is a spatial and temporal process in which energy is transported. A periodic wave is a wave that repeats as a function of position and time. Mathematically, periodic waves are used to describe oscillations and simple harmonic motion, which describes the movement of spring-mass systems. This type of wave is described by two characteristics: a magnitude and a phase. In this article, we will discuss the concept of the phase angle in a periodic wave.
In previous articles, we discussed the differential equation that describes oscillatory movement, particularly simple harmonic motion. We know the solution that satisfies the equation is expressed as
$$x=A\sin\left(\omega t+\phi_0\right).$$
Where \(A\) is the amplitude in meters \((\mathrm m)\), \(\omega\) is the angular frequency in radians per second \((\frac{\mathrm{rad}}{\mathrm s})\), and \(\phi_0\) is the initial phase in radians \((\mathrm{rad})\).
The phase angle is the angular component of a periodic wave, such that it is defined as the argument of the sine function, \(\omega t+\phi_0\). By choosing \(\phi_0\), we specify the oscillating object's initial position to make sure we have the correct equation with the oscillator's position, no matter where it may have been located at \(t=0\). We can restate the above equation in terms of the symbol \(\phi\) for the phase angle.
$$\begin{align*}\phi&=\omega t+\phi_0,\\x&=A\sin\left(\phi\right).\end{align*}$$
To determine the initial phase we use the following formula:
$$\phi_0=\sin^{-1}\left(\frac{x_0}A\right),$$
where \(A\) is the amplitude in meters \((\mathrm m)\) and \(x_0\) is the initial position of the object at \(t=0\) in meters \((\mathrm m)\).
A simple harmonic oscillator has an amplitude of \(3.0\;\mathrm{cm}\) and a frequency of \(4.0\;\mathrm{Hz}\). At time \(t=0\), its position is \(y=3.0\;\mathrm{cm}\). Where is it at time \(t=0.3\;\mathrm s\)?
The amplitude is \(A=0.03\;\mathrm m\) and the angular frequency is \(\omega=2\pi f=2\pi(4.0\;\mathrm{Hz})=8\pi\;{\textstyle\frac{\mathrm{rad}}{\mathrm s}}\). Now we can determine the initial phase,
\begin{align*}\phi_0&=\sin^{-1}\left(\frac{y_0}A\right),\\\phi_0&=\sin^{-1}\left(\frac{0.03\;\mathrm m}{0.03\;\mathrm m}\right),\\\phi_0&=\frac\pi2.\end{align*}
Now we know the position of the oscillator at any moment in time,
$$y(t)=0.03\sin\left(8\pi t+\frac\pi2\right).$$
We can find the position of the oscillator at time \(t=0.3\;\mathrm s\),
\begin{align*}y(0.3\;\mathrm s)&=(0.03\;\mathrm m)\sin\left((8\pi\;{\textstyle\frac{\mathrm{rad}}{\mathrm s}})(0.3\;\mathrm s)\;+\;\frac\pi2\;\mathrm{rad}\right),\\y(0.3\;\mathrm s)&=0.0093\;m.\end{align*}
The position of an oscillator is given by the equation:
$$y=(0.04\;\mathrm m)\sin\left((6\pi\;{\textstyle\frac{\mathrm{rad}}{\mathrm s}})t-\frac\pi2\;\mathrm{rad}\;\right).$$
Where is the oscillator at time \(t=0\)?
\begin{align*}y(0\;\mathrm s)&=(0.04\;\mathrm m)\sin\left((6\pi\;{\textstyle\frac{\mathrm{rad}}{\mathrm s}})(0\;\mathrm s)-\frac\pi2\;\mathrm{rad}\;\right),\\y(0\;\mathrm s)&=-0.04\;\mathrm m.\end{align*}
The initial phase will determine if a sine or cosine function is used to describe the position of the oscillating object. For example, if \(\phi_0=\frac\pi2\) we can use a cosine function instead of a sine function with the initial phase. This is due to the trigonometric identity, \(\sin\left(\frac\pi2+\theta\right)=\cos\left(\theta\right)\). The table below clarifies how the two expressions yield the same results at any time.
Equation | \(t=0\) | \(t=\frac\pi{2\omega}\) |
\(\sin\left(\omega t+\;\frac\pi2\right)\) | 1 | 0 |
\(\cos\left(\omega t\right)\) | 1 | 0 |
As a side note, the phase angle plays a very important role in experimental physics, especially in electronics where there is a direct relationship between the voltage and sinusoidal functions. In electronics, the phase angle refers to the angular displacement between the voltage and current waveforms in an alternating current circuit.
We have covered the theoretical definition of the phase angle and the initial phase. How do we understand the impact of changing the initial phase of a sinusoidal function? It is easier to understand if we actually represent the sinusoidal functions in a graph.
From the image above we see that at the initial value \(x=0\), \(f(0)=\sin\left(0\right)=0\). For the same sine function with an initial phase \(\phi_0=\frac{-\pi}4\), \(f(0)=\sin\left(0-\frac\pi4\right)=-\frac{\sqrt2}2\) and \(f(\frac\pi4)=\sin\left(\frac\pi4-\frac\pi4\right)=0\). We notice that the sine function has shifted horizontally to the right by an amount of \(\frac\pi4\). If we change the initial phase to \(\phi_0=-\pi\), we notice that the sine function shifts to the right by an amount of \(\pi\). We notice a pattern here, a negative initial phase will shift the function horizontally to the right, while a positive initial phase will shift the function horizontally to the left. This is visually represented in the figure below.
To find the phase angle at a certain moment in time you must multiply the angular frequency by the time and add the sum of the initial phase: wt+initial phase.
To find the phase angle at a certain moment in time you must multiply the angular frequency by the time and add the sum of the initial phase: wt+initial phase.
The phase angle is the angular component of a periodic wave, such that it is defined as the argument of the sine function, wt+initial phase.
To describe the phase angle at a certain moment in time you must multiply the angular frequency by the time and add the sum of the initial phase: wt+initial phase.
For example, a wave with angular frequency of pi and an initial phase of pi over 2 at the initial moment of the oscillation when time is zero, will have a phase angle of pi over 2. Remember that the phase angle is given by wt+initial phase.
What type of functions are used to describe oscillating systems like spring-mass systems?
Quadratic function.
The phase angle is the angular component of a periodic wave, such that it is defined as the argument of the sine function:
\(\omega t+\phi_0\).
By choosing \(\phi_0\), we specify the oscillating object's ___ to make sure we have the correct equation with the oscillator's position, no matter where it may have been located at \(t=0\).
initial position.
To find the initial phase, we must use the following equation:
\(\phi_0=\sin^{-1}\left(\frac{x_0}A\right)\).
The following expressions yield the same outputs:
\(x=A\cos(\omega t)\).
A negative initial phase will shift the function horizontally to the ___, while a positive initial phase will shift the function horizontally to the ___.
right, left.
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