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So how can we tell things apart if they aren't labeled? Chemists utilize a technique called **elemental analysis **to figure out the composition of compounds. Using this technique, it would be easy to distinguish between sugar and salt and avoid another ruined coffee! In this article, we will take a look at elemental analysis and all its uses within chemistry.

- This article covers
**elemental analysis**. - First, we discuss the different
**applications**of elemental analysis. - Next, we cover its different
**methods**. - Then, we walk through a
**general procedure**. - Lastly, we learn about the
**formula**used in elemental analysis and walk through an**example**.

## Applications of elemental analysis

**Elemental Analysis **is a process where a sample is analyzed for its elemental and sometimes isotopic composition.

**Isotopes** are different forms of the same element with the name number of protons, but a different number of neutrons

For isotopic composition, we would be determining the amount of different isotopes. For example, seeing the amount of carbon-12 versus carbon-14.

The first thing to think about regarding elemental analysis is understanding why you would use this technique. One important use would be for tissue and or blood samples. If you need to know what elements a tissue/blood sample was exposed to, then you would use elemental analysis to figure it out. In the discipline of Toxicology, elemental analysis is an often-used technique in analyzing substances.

Elemental analysis has wide applications in many scientific industries, such as pharmaceutical industrial work, research, geology, materials science, environmental science, and many more. If bulk analysis needs to be done, such as in the pharmaceutical industry, then the most common method would be X-ray fluorescence. Elemental analysis is a crucial analytical technique in many research fields and is used throughout the world as a premier way to analyze the elemental composition of substances.

## Elemental Analysis Methods

Now that we know *why *someone would use elemental analysis, let's dive into the *how. *

There are **four standard methods** of conducting elemental analysis using **instruments**:

- X-ray fluorescence.
- Atomic absorption.
- Inductively coupled plasma - mass spectrometry.
- inductively coupled plasma - optical emission spectroscopy.

Each of these analytical techniques has its own benefits, and all four are commonly used in labs throughout the world.

Mass spectrometry is the most common method to conduct elemental analysis (we will also be walking through an example later). Since it's the most common, we are going to dive a little deeper and walk through the steps:

- A sample is ionized - usually an electron is lost to form a
**cation**(positively charged ion). - The ions are sorted and separated based on their mass and charge.
- The separate ions are measured, and the data is displayed on a chart.
- The data will have mass/charge (m/z) on the x-axis and relative abundance on the y-axis.

Below is an image of a mass spectrometer:

By performing mass spectrometry, results for the **percent composition** of each element are elucidated (which we will discuss later), which are used to determine the** molecular**** chemical formula.**

The **molecular chemical formula** gives us the exact ratio of elements. This formula is different from the **empirical chemical formula**,** **which tells us the smallest ratio of elements within a molecule. For example, the empirical formula would give us NO_{2}, while the molecular formula is actually N_{2}O_{4}.

## Elemental Analysis Procedure

Now that we are familiar with the different methods, let's walk through how to use them. When conducting elemental analysis, there are two types of analysis: a **qualitative **and **quantitative analysis**.

**Qualitative analysis **focuses on determining *what *elements are in a sample, while **quantitative analysis **measures the *amount of each *element in the sample.

The general procedure for qualitative analysis is as follows:

- Choose a method to use for the sample.
- Using the chosen method, you obtain the identity of the elements.

The quantitative procedure is the same, except it measures the **percent composition.**

**Percent composition **is the total percentage of an element within a molecule.

- Choose a method to use for the sample
- Using the chosen method, obtain the percent composition
- Using the percent composition, calculate the empirical or molecular formula (whichever is relevant for the method chosen)

## Elemental Analysis formula

For whichever method we use, it will spit out a chart showing the percent composition.

Using atomic absorption, the following percent composition data were obtained: 40.9 % Carbon (C), 4.57 % Hydrogen (H), and 54.5 % Oxygen (O). What is the empirical formula of the sample?

Our first step is to convert from a percentage to grams. We can assume that the total gram amount is 100 g. Technically, we can choose any amount since the ratio will be the same, but this method is simpler. Doing this conversion, we get:

\(100\,g*40.9\%=40.9\,g\,C\)

\(100\,g*4.57\%=4.57\,g\,H\)

\(100\,g*54.5\%=54.5\,g\,O\)

Next, we need to convert to moles. This is because the empirical formula (and all chemical formulas) are in units of moles. To do this, you divide the number of moles by each element's **atomic mass, **which is the amount of grams of the element per mole. It is also the weight listed under the element on the periodic table.

\(\frac{40.9\,g}{\frac{12.01\,g}{mol}}=3.41\,mol\,C\)

\(\frac{4.57\,g}{\frac{1.01\,g}{mol}}=4.52\,mol\,H\)

\(\frac{54.5\,g}{\frac{16.00\,g}{mol}}=3.41\,mol\,O\)

Our last step is to divide each molar amount by the smallest variable. Doing so will give us the ratio between elements.

\(\frac{3.41\,mol\,C}{3.41}=1\,C\)

\(\frac{4.52\,mol\,H}{3.41}=1.33\,H\)

\(\frac{3.41\,mol\,O}{3.41}=1\,O\)

We have a ratio of 1:1.33:1; however, chemical formulas are in whole numbers. So what do we do? Well, we multiply our ratio by the smallest number possible to get all whole numbers. In this case, that number is 3.

\(1\,C*3=3\,C\)

\(1.33\,H*3=4\,H\)

\(1\,O*3=3\,O\)

So our final formula is:

\(C_3H_4O_3\)

A key thing to note is that calculating the molecular formula is the same steps, except we would be using *exact *gram amounts and not estimated ones.

Let's walk through an example:

Using atomic absorption, the following percent composition data were obtained: 85.6 % Carbon (C) and 14.4 % Hydrogen (H). What is the molecular formula of the sample if the total mass is 84.16 g?

Since we know the actual mass, we will multiply the percentages by that mass:

\(84.16\,g*85.6\%=72.1\,g\,C\)

\(84.16\,g*14.4\%=12.1\,g\,H\)

Now we convert from grams to moles:

\(\frac{72.1\,g}{\frac{12.01\,g}{mol}}=6\,mol\,C\)

\(\frac{12.1\,g}{\frac{1.01\,g}{mol}}=12\,mol\,H\)

So the molecular formula is:

\(C_{6}H_{12}\)

## Elemental analysis example

Now that we've covered all of our basics, it's time for an example!

An unknown gaseous sample was analyzed using a mass spectrometer, giving the data below. What is the molecular formula of the sample?

Our first step is to understand what this data is telling us. Mass spectrometry breaks things into *fragments,* not necessarily elements, so each peak is a fragment *or *an element. The peak that has 100% intensity is the peak for the molecule itself, so we know that the entire molecule has a mass of 44 g.

This means that the other peaks are either elements or fragments (i.e., smaller molecules). Let's label each peak, going from left to right.

The first peak is 12 g, which means it is carbon, which has an atomic mass of 12 g/mol. The second peak is 16 g, so it is oxygen (oxygen has an atomic mass of 16 g/mol).

Now for the 28 g peak. It could be either silicon or carbon monoxide (CO), which both have masses of 28 g/mol. We know that this sample is a gas, so it is more likely that this is CO and not silicon (which is usually a solid). This also makes sense since the total mass of the sample is 44 g, and the mass of C+O+Si is 56 g.

Now that we know our peaks, we can determine the identity of the sample. So we know that the molecule contains two elements: C and O, so we can subtract those masses from the total mass.

\(44-(12.00+16.00)=16.00\)

Since there are 16 g "left over", that means there is another oxygen atom present, so the complete formula is \(CO_2\)

## Elemental Analysis - Key takeaways

**Elemental Analysis**is a process where a sample is analyzed for its elemental and sometimes isotopic composition.- The
**molecular chemical formula**gives us the exact ratio of elements. This is different from the**empirical chemical,**which tells us the smallest ratio of elements within a molecule. **Qualitative analysis**focuses on determining*what*elements are in a sample, while**quantitative analysis**measures the*amount of each*element in the sample.**Percent composition**is the total percentage of an element within a molecule.- The basic steps of elemental analysis are:
- Choose a method to use for the sample.
- Using the chosen method, obtain the percent composition.
- Using the percent composition, calculate the empirical or molecular formula (whichever is relevant for the method chosen).

## References

- Fig. 1 - A mass spectrometer (https://upload.wikimedia.org/wikipedia/commons/thumb/5/50/Thermo_-_Finnigan_LCQ_Mass_Spectrometer_%2815797493459%29.jpg/640px-Thermo_-_Finnigan_LCQ_Mass_Spectrometer_%2815797493459%29.jpg) by Kitmondo LAB (https://www.flickr.com/people/129143611@N03) licensed by CC BY 2.0 (https://creativecommons.org/licenses/by/2.0/)

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##### Frequently Asked Questions about Elemental Analysis

What is elemental analysis?

**Elemental Analysis **is a process where a sample is analyzed for its elemental and sometimes isotopic composition.

What is elemental analysis used for?

Elemental analysis is used to identify the elemental or isotopic composition of a sample. It is used in the fields of toxicology, research geology, environmental science, and many others.

How do you calculate formulas using elemental analysis?

From elemental analysis, we get the percent composition. We multiply each element's percent composition by the total gram amount to get the number of grams per element. Then, you divide each gram amount by the molar mass to get the amount of moles. You then divide each molar amount by the smallest molar amount to get the ratio between elements (the formula).

What is elemental analysis of organic compounds?

Organic compounds like blood and tissue are commonly analyzed using elemental analysis. The process is the same for inorganic and organic compounds.

What are methods of elemental analysis?

There are 4 main methods of elemental analysis: X-ray fluorescence, atomic absorption, mass spectrometry, and optical emission spectroscopy.

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