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Think about the oxidation of metals. During an oxidation reaction, a substance gains oxygen. But, did you know that oxidation is considered a thermodynamically favored process in air, at room temperature?
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Jetzt kostenlos anmeldenThink about the oxidation of metals. During an oxidation reaction, a substance gains oxygen. But, did you know that oxidation is considered a thermodynamically favored process in air, at room temperature?
If you are curious about what this means, let's dive into Gibbs Free Energy and thermodynamic favorability!
Before exploring what drives reactions to be thermodynamically favorable, let's review the laws of thermodynamics, Entropy (S), and enthalpy (H).
There are three laws of thermodynamics. The first law states that the universe has a constant energy. In other words, energy cannot be created nor destroyed, only transferred between the system and the surroundings.
$$\Delta E_{universe}\cup =\Delta E_{system}+\Delta E_{surroundings}=0$$
The second law of thermodynamics tells us that, over time, the Entropy of the universe will increase. Now, the third law of thermodynamics states that the entropy of a perfect crystal at zero K is 0.
To keep learning about this, check out "The Laws of Thermodynamics"!
Let's look at the definitions of entropy and enthalpy. Entropy (S) is a measurement of the disorder (randomness) of a system. The larger this value, the greater the randomness a system has. The change in entropy is given by the following equation.
$$\Delta S^{o}=S^{o}_{products}-S^{o}_{reactants}$$
Enthalpy (H), is referred to as the heat energy that a reaction has. Basically, if the change in enthalpy (ΔH) is less than zero, then the reaction will be exothermic. If ΔH surpasses zero, the reaction is considered endothermic.
Exothermic reactions are reactions that transfer energy from the reacting substance to the surroundings. In an exothermic reaction, the temperature of the solution increases.
In endothermic reactions, energy is transferred from the surroundings to the reacting substance, and the temperature of the solution decreases.
The formula for change in enthalpy is shown below.
$$\Delta H^{o}=\Sigma n\Delta H^{o}_{products}-\Sigma n\Delta H^{o}_{reactants}$$
Now, let's define thermodynamically favorability.
Being thermodynamically favorable means that the reaction can proceed without any assistance from outside the system. For example, NaCl dissolving in water is a thermodynamically favored process
If a process can occur without outside help once the Activation Energy has been reached, then this process is said to have thermodynamic favorability.
A thermodynamically favored process is thermodynamically favored in one direction, and non-thermodynamically favored in the other direction. But, what does this mean? Let's use water as an example. Water can go from liquid to solid at -10 °C, but it cannot go from solid to liquid at this temperature. So,
A non-thermodynamically favored process is considered a process that needs assistance from outside the system. These reactions can be forced to proceed if we apply an external source of energy to it.
The standard Gibbs Free Energy change is used by chemists as a measure of thermodynamic favorability. The equations below can be used to calculate ΔG°.
$$\Delta G^{o}_{reaction}=\Sigma [G^{o}_{f}(products)]-\Sigma [G^{o}_{f}(reactants)]$$
$$\Delta G^{o}_{reaction}=\Delta H^{o}-T\Delta S^{o}$$
Where:
When dealing with Gibbs Free Energy, we can say that a reaction will be thermodynamically favored if ΔG° < 0 and there is no need for an external source of energy.
Some textbooks might use the terms spontaneous and nonspontaneous to describe thermodynamically favorable and thermodynamically unfavorable reactions. But, expect to see favorable and unfavorable in your AP exam! To get a better in-depth explanation on Gibbs Free Energy, check out "Gibbs Free Energy".
Think about exothermic and endothermic reactions, and choose which one of these you think is most often thermodynamic favored. If you guessed exothermic reactions, then you are right!
Exothermic reactions are usually thermodynamically favored because they release energy to the surroundings. However, some endothermic reactions can also be thermodynamically favored. For example, evaporation is an endothermic process that is thermodynamically favored.
$$H_{2}O_{(l)}\rightarrow H_{2}O_{(g)}\ \ \ \ \Delta H^{o}=+40.7kJ$$
$$C_{3}H_{8\ (l)}\rightarrow C_{3}H_{8\ (g)}\ \ \ \ \ \Delta H^{o}=+16.7kJ$$
Increases in entropy (S) are also thermodynamically favorable. The general rule is that if the entropy of the universe (thermodynamic system plus its surroundings) is positive, then the reaction is thermodynamically favored. If ΔSuniverse is negative, then the reaction is not thermodynamically favored.
$$\Delta S_{universe}=\Delta S_{system}+\Delta S_{surroundings}$$
When does entropy increase? Entropy increases when:
Did you know that we can combine thermodynamically unfavored reactions with thermodynamically favored reactions to create an overall thermodynamically favorable process? This is known as coupling, and you can learn about this on "Coupled Reactions"!
To make things simpler, let's make a chart showing thermodynamic favorability, considering changes in entropy and changes in enthalpy.
Change in Entropy | Change in Enthalpy | Gibbs Free Energy | Thermodynamically Favored? |
Negative | Negative | Temperature-dependent | Only at low temperatures |
Positive | Negative | Negative | Yes |
Negative | Positive | Positive | No |
Positive | Positive | Temperature-dependent | Only at high temperatures |
Let's look at the difference between reactions that are thermodynamically favorable and those that are kinetically favorable.
A reaction that is thermodynamically favorable usually occurs at slow rates and higher temperatures in a Reversible Reaction, and form stable products known as thermodynamic products.
Kinetically favorable reactions are the opposite; they are fast, can be carried out at low temperatures, and lead to the formation of unstable products. The products of kinetically favored reactions are called kinetic products.
As an example, let's use the addition of hydrogen bromide (HBr) to 1,3 butadiene. This reaction is commonly seen in Organic Chemistry courses, and it is an example of conjugated hydrohalogenation, or hydrohalogenation of dienes.
To top it off, let's look at an example involving a thermodynamically favored reaction. This first example asks us to determine if the following reaction is thermodynamically favored.
The table below gives some important values for the reaction between H2S and O2 at 298K. Use this table to predict whether the reaction is thermodynamically favored.
$$H_{2}S_{(g)}+2O_{2\ (g)}\rightleftharpoons H_{2}SO_{4\ (g)}$$
H2S | O2 | H2SO4 | |
-20 | 0 | -814 | |
206 | 205 | 157 | |
-33 | 0 | -690 |
First, we need to make sure everything has the same units. Notice that entropy is in J, while the others are in kJ. So, the converted values for ΔS° (kJ/K·mol) are 0.206, 0.0205, and 0.157.
Now, we need to calculate for the reaction using the following formulas:
$$\Delta S_{universe}=\Delta S_{system}+\Delta S_{surroundings}$$
$$\Delta S^{o}=[1(0.157)]-[1(0.206)+2(0.205)]=-0.459kJ/K\cdot mol$$
$$\Delta H^{o}=\Sigma n\Delta H^{o}_{products}-\Sigma n\Delta H^{o}_{reactants}$$
$$\Delta H^{o}=[1(-814)]-[1(-20)]=-749kJ/mol$$
$$\Delta G^{o}=\Sigma [G^{o}_{f}(products)]-\Sigma [G^{o}_{f}(reactants)]$$
$$\Delta G^{o}=[1(-690)]-[1(-33)]=-657kJ/mol$$
A reaction that has a negative entropy, a negative enthalpy, and a negative Gibbs free energy value, is said to be thermodynamically favorable.
Now, I hope that you feel more familiar with the concept of thermodynamic favorability!
If a process can occur without outside help once the activation energy has been reached, then this process is said to have thermodynamic favorability.
Being thermodynamically favorable means that the reaction can proceed without any assistance from outside the system.
Yes, spontaneously reactions are thermodynamically favorable reactions. So, they are energetically favorable because they don't need outside energy to proceed.
A thermodynamically unfavorable process is considered a process that needs assistance from outside the system. These reactions can be forced to proceed if we apply an external source of energy to it.
However, some endothermic reactions can also be thermodynamically favored. For example, evaporation is an endothermic process that is thermodynamically favored.
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SIGNUP SIGNUPFlashcards in Thermodynamically Favored14
Start learningThe _____ law of thermodynamics states that energy of the universe is constant
first
______ is a measurement of the disorder (randomness) of a system.
Entropy
If the change in enthalpy (ΔH) is less than zero, then the reaction will be _____.
exothermic
If the change in enthalpy (ΔH) is greater than zero, then the reaction will be _____.
endothermic
_______ reactions are reactions that transfer energy from the reacting substance to the surroundings.
Exothermic
In _______ reactions, energy is transferred from the surroundings to the reacting substance, and the temperature of the solution decreases.
endothermic
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