Americas
Europe
Explore our app and discover over 50 million learning materials for free.
Lerne mit deinen Freunden und bleibe auf dem richtigen Kurs mit deinen persönlichen Lernstatistiken
Jetzt kostenlos anmeldenWe’ve previously gone over the importance of Spectroscopy, and the role it plays in determining sample characteristics and identity. In that lesson, we went over the four types of spectroscopy that are covered on the AP Chemistry exam, and what you need to know for each of them. However, spectroscopy is a concept that doesn’t go away as you advance into higher-level chemistry courses. It just so happens that Photoelectron Spectroscopy is one of the most mentioned on the AP Chemistry exam. Therefore, we think it’s worthwhile to take a deeper look at the theory behind how PES operates, and what happens when certain ions and molecules are tested.
Let's begin with the theory behind Photoelectron Spectroscopy. What purpose does PES have, what qualities does it attempt to detect in samples, and how does it try to do that? Let's start with the first question.
As defined in our Spectroscopy lesson, Photoelectron Spectroscopy (PES) detects the ionization energy from removing electrons one by one with X-ray or UV radiation. This reveals information about individual atoms and their orbitals in samples that are gaseous or solid.
So, photoelectron spectroscopy plucks electrons off of an atom or molecule to reveal the structure of the sample. It broadly does this through two different methods: UV radiation and X-ray radiation. It should be noted that X-ray photons have a significantly higher energy level than UV photons.
If you need a refresher on the Electromagnetic Spectrum, refer to our general lesson on Spectroscopy. Photoelectron Spectroscopy is also rooted in something called the Photoelectric Effect. We have a lesson on this as well (just click the link)!
But what is this useful for? This is where the two main types of PES come into play.
For both types of photoelectron spectroscopy, three fundamental features allow chemists to probe a sample.
First, a high-energy EM radiation source. Obviously, for UV PES a source of ultraviolet radiation is used, and for X-ray PES, X-ray radiation is used.
Second, a detector that can pick up the kinetic energy given off by plucked-off electrons. This kinetic energy is proportional to the ionization energy needed to remove the electron.
Third, this has to take place within a vacuum to prevent any atmospheric noise.
A typical PES experiment would be set up like this:
Figure 1: Drawn example of a Photoelectron Spectrometer
But of course, these different variables can change based on what kind of PES experiment you want to perform.
If you're thinking about the structure of an atom, there are traditionally two different regions: the nucleus and the electron cloud. The second has been represented as shells historically, and while the reality of the situation might be a bit different, this model is useful for visualizing how PES operates. We know that PES plucks off electrons from an atom. But from what shell? Are these electrons picked at random, or is there some order to their selection?
This reveals a key difference between UV PES and X-ray PES, and why there are multiple types of PES, to begin with. The higher the energy the EM source has, the more subshells can be probed and the closer chemists can get to the nucleus.
If you recall from the Electromagnetic Spectrum, UV radiation has less energy than X-ray radiation. This means that UV PES is used to target electrons on valence shells, while X-ray PES can reach shells closer in proximity to the nucleus.
Let's start with describing UV PES, as its purpose and mechanisms are much more simple than X-ray PES. UV radiation has significantly less energy (typically measured in eV) than X-ray radiation. To give a visualization of this, UV photons typically have energy in a range of 1 eV to 100 eV. X-ray photons can have energy from 100 eV up to 100,000 eV! That’s 1000x stronger! It's clear from this comparison why X-ray PES has far more atomic penetration than UV.
Using the less powerful UV radiation source, chemists can probe and study the valence orbital of electrons in a sample.
But why would chemists want to isolate the valence electrons of a sample? There are a few good reasons they might want to do this.
But what if we want to look deeper into a sample? This is where X-ray PES comes into play. At this point in your AP Chemistry studies, you've most certainly been familiarized with atomic orbitals, and how every element has a unique Electron Configuration. As it turns out, X-ray PES attempts to turn this principle into a tangible, detectable property. X-ray PES is primarily used to determine the elemental composition of a sample by analyzing the orbitals that are present- which correlates to the aforementioned electron configuration.
What can chemists do with the power of X-ray PES? The range of applications is much more than UV PES!
To familiarize yourself with what a PES spectrum looks like, here's the example that was provided in our general Spectroscopy article.
Figure 2. Drawn example of nitrogen under Photoelectron Spectroscopy
Above, there is a PES spectrum of a pure, idealized sample of nitrogen. We know that nitrogen has an Electron Configuration of 1s22s22p1 in its ground state. Analyzing the PES of our nitrogen gas sample, we can see that we have three peaks that correspond with the three discrete levels of energy. We can also see that the height of the peaks is relative to how many electrons are in each subshell. For example, the first two peaks are equal in height because 1s2 and 2s2 both have 2 electrons. The third peak, which represents 2p is half in height because there is only one electron in its subshell. This technique can be applied to the PES spectrum to determine what element is being analyzed.
For an easy example such as a sample of pure nitrogen, the PES spectrum is pretty easy to analyze. If you can recall a problem that involves a complicated electron configuration, however, it's pretty easy to see how quickly things can get complicated. But, as long as you keep track of the relative size of each peak and write down the associated orbital that goes with them, you should be able to keep things clear.
Let's try to walk through an additional, more complicated PES graph. Go ahead and try to read the spectrum below, and once you've finished your attempt, we can walk through it together.
This PES spectrum is representative of Argon! We know that the electron configuration of argon is 1s2 2s2 2p6 3s2 3p6. These peaks can be correlated to their respective orbitals based on their relative heights. It should also be noted that these peaks are grouped relatively based on what their shell is. That means 1s2 is by itself, 2s2 and 2p6 are together in the 2nd group, and 3s2 and 3p6 are together in the 3rd group. This pattern would continue into higher-level shells.
For higher-level PES problems, chemists will integrate these peaks to determine elemental ratios. However, the AP Chemistry exam primarily focuses on spectrum identification and peak assignment.
We hope that this in-depth lesson about Photoelectron Spectroscopy helps you to understand why PES is useful to chemists, how PES might appear on the AP Chemistry exam, and how to interpret spectra problems.
The energy of a quantum of EM radiation from the light source is hν :
$$E_{quantum}=hν$$
Where, h, is Planck's constant equal to, and ν, is the frequency of the radiation.
According to Einstein's theory of the Photoelectric Effect, the kinetic energy, (KEelectron ), of an electron that is knocked off of a molecule is:
$$KE_{electron}=hν−hν_0$$
Where, hν, is the energy of the incoming quantum and, hν0, is the energy required to promote an electron from a bound state to a positive ion state. In terms of the electron binding energy, (BEelectron = hν0), the kinetic energy of the electron emitted from the molecule is:
$$KE_{electron}=hν−BE_{electron}$$
Then, moving (BEelectron ) to the left-hand side, we get:
$$KE_{electron}+BE_{electron}=hν=E_{quantum}$$
Where, hν = Equantum, is the energy of the incoming EM radiation, KEelectron, is the kinetic energy of the electron emitted from the molecule, and, BEelectron, is the binding energy of an electron in a molecule. Lastly, we note that the binding energy of an electron in a molecule:$$BE_{electron}=E_{quantum}−KE_{electron}$$
For both types of photoelectron spectroscopy, three fundamental features allow chemists to probe a sample.
First, a high-energy EM radiation source. Obviously, for UV PES a source of ultraviolet radiation is used, and for X-ray PES, X-ray radiation is used.
Second, a detector that can pick up the kinetic energy given off by plucked-off electrons. This kinetic energy is proportional to the ionization energy needed to remove the electron.
Third, this has to take place within a vacuum to prevent any atmospheric noise.
Photoelectron Spectroscopy (PES) detects the ionization energy from removing electrons one by one with X-ray or UV radiation. This reveals information about individual atoms and their orbitals in samples that are gaseous or solid.
To determine a molecular formula from photoelectron spectroscopy (PES), you look at the peaks in the PES graph. These peaks can be correlated to their respective orbitals based on their relative heights.
The x-axis of a photoelectron spectrum is ionization energy, while the y-axis is the number of electrons. By looking at the different peaks, we can determine which orbitals they belong to.
Yes, PES can give the percentage of atoms.
Photoelectron Spectroscopy (PES) detects the ionization energy from removing electrons one by one with X-ray or UV radiation.
Flashcards in Ion and Atom Photoelectron Spectroscopy15
Start learningWhat are the three components of PES?
A high-energy EM radiation source, an electron detector, and a vacuum environment.
What principle is PES based on?
The photoelectric effect
What units are used in a PES spectrum?
Ionization energy vs # of electrons detected
What does each peak represent?
An electron subshell
What is each peak's height based off of?
Relative electron abundance (think the subscript in electron configurations)
How are peaks grouped?
Based on orbitals (think the coefficients of electron configurations)
Already have an account? Log in
60%
of the users don't pass the Ion and Atom Photoelectron Spectroscopy quiz! Will you pass the quiz?
Start QuizHow would you like to learn this content?
How would you like to learn this content?
Free chemistry cheat sheet!
Everything you need to know on . A perfect summary so you can easily remember everything.
The first learning app that truly has everything you need to ace your exams in one place
Sign up to highlight and take notes. It’s 100% free.
Save explanations to your personalised space and access them anytime, anywhere!
Sign up with Email Sign up with AppleBy signing up, you agree to the Terms and Conditions and the Privacy Policy of StudySmarter.
Already have an account? Log in
Explanations 
Exams 
Magazine 
