Algebra

**Algebra **is the branch of mathematics that represents problems as mathematical expressions, using **letters or variables** (i.e. x, y or z) to represent unknown values that can change. The purpose of algebra is to find out what the unknown values are, to find a solution to a problem.

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Jetzt kostenlos anmelden**Algebra **is the branch of mathematics that represents problems as mathematical expressions, using **letters or variables** (i.e. x, y or z) to represent unknown values that can change. The purpose of algebra is to find out what the unknown values are, to find a solution to a problem.

Algebra combines numbers and variables using mathematical operations like addition, subtraction, multiplication and division to represent a specific problem. The solutions to the problems are found by using predefined rules to manipulate each mathematical expression.

An **example of an algebraic expression** is:

\(3x+2=5\)

In this example, **x** is the unknown value, 3 is the coefficient of **x**, 2 and 5 are constants (fixed values), and the operation being performed is an addition (+).

Remember that the coefficient is the number that is multiplied by a variable

Algebra can be classified into different **sub-branches **according to the level of complexity of their algebraic expressions and where they are applied. These branches range from elementary algebra to more abstract and complex equations, which require more advanced mathematics. Elementary algebra deals with solving algebraic expressions to find a solution, and it is used in most fields like science, medicine, economics and engineering.

Abu Ja'far Muhammad ibn Musa al-Khwarizmi invented algebra. He was a writer, scientist, astronomer, geographer, and mathematician, born in the 780s in Baghdad. The term **algebra **comes from the Arabic word **al-jabr**, which means "the reunion of broken parts".

Being able to understand algebra not only helps you to represent algebraic expressions and find their solutions. It also allows you to improve your problem-solving skills, helping you to think critically and logically, identify patterns, and solve more complex problems involving numbers and unknown values.

Knowledge of algebra can be applied to solve everyday problems. A business manager can use algebraic expressions to calculate costs and profits. Think about a shop manager that wants to calculate the number of chocolate milk cartons sold at the end of the day, to decide whether to continue stocking them or not. He knows that at the start of the day he had 30 cartons in stock, and at the end, there were 12 left. He can use the following algebraic expression:

\(30 - x = 12\) x is the number of chocolate milk cartons sold

We need to work out the value of x by solving the expression above:

\(30 - 12 = x\) isolating x to one side of the equation and solving the operation

**x = 18**

The number of chocolate milk cartons sold on that day was 18.

This is just a simple example, but the benefits of understanding algebra go a lot further than that. It helps us with daily activities like shopping, managing a budget, paying our bills, planning a holiday, among others.

The degree of an algebraic equation is the highest power present in the variables of the equation. Algebraic equations can be classified according to their degree as follows:

Linear equations are used to represent problems where the degree of the variables (i.e. x, y or z) is one. For example, \(ax+b = 0\), where x is the variable, and a and b are constants.

Quadratic equations are generically represented as \(ax^2+bx+c = 0\), where x is the variable, and a, b and c are constants. They contain variables with power 2. Quadratic equations will produce two possible solutions for **x** that satisfy the equation.

Cubic equations are represented in a generic form as \(ax^3 + bx^2+cx +d=0\), where x is the variable, and a, b, c and d are constants. They contain variables with power 3.

The basic properties of algebra that you need to keep in mind when solving algebraic equations are:

**Commutative property of addition:**Changing the order of the numbers being added does not change the sum.

\(a + b = b + a\)

**Commutative property of multiplication:**Changing the order of the numbers being multiplied does not change the product.

\(a \cdot b = b \cdot a\)

**Associative property of addition:**Changing the grouping of the numbers being added does not change the sum.

\(a + (b +c) = (a+b)+c\)

**Associative property of multiplication:**Changing the grouping of the numbers being multiplied does not change the product.

\(a \cdot (b \cdot c) = (a \cdot b) \cdot c\)

**Distributive property:**If you multiply the sum of two or more numbers by another number, you will get the same result as multiplying each term in the sum individually by the number and then adding the products together.

\(a \cdot (b +c)= a \cdot b + a \cdot c\)

**Reciprocal:**You can find the reciprocal of a number by swapping the numerator and the denominator.

Reciprocal of \(a = \frac{1}{a}\)

**Additive identity:**If you add 0 (zero) to any number, you will get the same number as a result.

\(a + 0 = 0 + a = a\)

**Multiplicative identity:**If you multiply any number by 1, you will get the same number as a result.

\(a \cdot 1 = 1 \cdot a =a\)

**Additive inverse:**Adding a number and its inverse (same number with opposite sign) gives 0 (zero) as a result.

\(a + (-a) = 0\)

**Multiplicative inverse:**If you multiply a number by its reciprocal, you will get 1 as a result.

\(a \cdot \frac{1}{a} = 1\)

To solve linear algebraic equations, you should follow the following steps:

**Step 1:**each side of the equation must be simplified by removing parentheses and combining terms**Step 2:**add or subtract to isolate the variable on one side of the equation**Step 3:**multiply or divide to obtain the value of the unknown variable

\(3 (x + 1) + 4 = 16\)

**Step 1:**\(\begin{align} 3x + 3 + 4 = 16 \\ 3x + 7 = 16 \end{align}\)**Step 2:**\(\begin{align} 3x = 16 - 7 \\ 3x = 9 \end{align}\)**Step 3:**\(\begin{align} x = \frac{9}{3} \\ x = 3 \end{align}\)

\(4x + 3 = x - 6\)

**Step 1:**We can skip this step as there are no parentheses in this equation**Step 2:**\(\begin{align} 4x - x = -6 - 3 \\ 3x = -9 \end{align}\)**Step 3: \(\begin{align} x = \frac{-9}{3} \\ x = -3 \end{align}\)**

You have a box of blue and red balls. The total of balls is 50, and the amount of red balls is twice the amount of blue balls minus 10. How many red balls are there in the box?

To solve word problems you need to follow this strategy:

Assign variables to unknown values

Construct the equations

Solve the equations

**Our variables are:**

B = amount of blue balls

R = amount of red balls

**Equations:**

1) \(B + R = 50\)

2) \(R = 2B - 10\)

**Now we solve the equations:**

We know that \(R = 2B - 10\), so we can substitute the value of R in equation 1 with that expression

\(B + (2B - 10) = 50\)

\(B + 2B - 10 = 50\)

\(3B = 50 + 10\)

\(3B = 60\)

\(B = \frac{60}{3}\)

**\(B = 20\)**

Now we substitute the value of B in equation 2:

\(R = 2B - 10\)

\(R = 2 \cdot 20 - 10\)

\(R = 40 - 10\)

**\(R = 30\)**

**There are 30 red balls in the box.**

The different types of problems that you can find in algebra vary depending on the type of algebraic expressions involved and their complexity. The main ones are:

Equations

Inequalities

Partial fractions

Algebra is a branch of mathematics that uses letters or variables to represent unknown values that can change.

Real-life problems can be represented using algebraic expressions.

Algebra uses predefined rules to manipulate each mathematical expression.

Understanding algebra helps to improve problem-solving skills, critical and logical thinking, identifying patterns, and skills to solve more complex problems involving numbers and unknown values.

The different types of algebraic equations according to their degree are: linear, quadratic and cubic.

To solve linear algebraic equations each side of the equation must be simplified by removing parentheses and combining terms, then add or subtract to isolate the variable on one side of the equation, and finally multiply or divide to obtain the value of the unknown variable.

To solve word problems start by assigning variables to unknown values, construct the equations, then solve the equations.

An example of an algebraic expression is: 3x + 2 = 5

In this example x is the unknown value, 3 is the coefficient of x, 2 and 5 are constants (fixed values), and the operation being performed is an addition (+).

To solve linear algebraic equations follow these steps:

- Each side of the equation must be simplified by removing parentheses and combining terms.
- Add or subtract to isolate the variable on one side of the equation.
- Multiply or divide to obtain the value of the unknown variable.

What is algebra?

Algebra is a branch of mathematics that represents problems as mathematical expressions, using letters or variables (ie x, y or z) to represent unknown values that can change. The purpose of algebra is to find out what the unknown values are, by using predefined rules to manipulate each mathematical expression.

What is the distributive property of algebra?

a × (b + c) = a × b + a × c

What is the commutative property of multiplication of algebra?

a × b = b × a

What is the associative property of addition of algebra?

a + (b + c) = (a + b) + c

What is the additive inverse property of algebra?

a + (-a) = 0

What are the steps to solve linear algebraic equations?

Step 1: each side of the equation must be simplified by removing parentheses and combining terms

Step 2: add or subtract to isolate the variable on one side of the equation

Step 3: multiply or divide to obtain the value of the unknown variable

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